A charged particle is projected in a magnetic field B = ( 3 i + 4 j ) × 1 0 − 2 T . The acceleration of the particle is found to be a = ( − 3 8 i ^ + y j ^ ) m / s 2 . Find the value of y.

Magnetic force is perpendicular to B, so a ⊥ B : a ⋅ B = 0 . ( − 3 8 ) ( 3 ) + ( y ) ( 4 ) = 0 ⇒ y = 2 .

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PhysicsMagnetismMotion analysis in electric & magnetic fieldMedium3 minQB

PhysicsMediuminteger

A charged particle is projected in a magnetic field $B = (3 i + 4 j) \times 1 0^{- 2} T$ . The acceleration of the particle is found to be $a = (- \frac{8}{3} \hat{i} + y \hat{j}) m / s^{2}$ . Find the value of y.

Answer:

Solution:

Magnetic force is perpendicular to B, so $a ⊥ B$ : $a \cdot B = 0$ .

$(- \frac{8}{3}) (3) + (y) (4) = 0 \Rightarrow y = 2$ .

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 3mℹ️ Source: QB

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