Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

PhysicsMediumsingle choice

A thin lens has curvature $R_{1} = 10 cm$ & $R_{2} = 20 cm$ , if medium of glass has refractive index 1.5. Find focus of mirror in air.

Answer:

Solution:

Lens maker's formula: $\frac{1}{f} = (μ - 1) (\frac{1}{R _{1}} - \frac{1}{R _{2}}) = (1.5 - 1) (\frac{1}{10} + \frac{1}{20}) = \frac{3}{40}$ .

So $f = \frac{40}{3} cm$ .

Answer: B

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

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