Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsMiscellaneousMedium3 minQB

PhysicsMediumnumerical range

Passage / Comprehension

A semi cylinder made of a transparent plastic has a refraction index of $n = 2$ and a radius of R . There is a narrow incident light ray perpendicular to the flat side of the semi cylinder at d distance from the axis of symmetry.\\

What can the maximum value of d (in cm) be so that the light ray can still leave the other side of the semi cylinder? [Take : $R = 10 cm$ ]

Answer:

7.04

Solution:

$sin θ_{C} = \frac{1}{2} \Rightarrow θ_{C} = 4 5^{\circ}$ . The ray hits the curved surface at incidence $sin i = \frac{d}{R}$ .

$d_{ma x} = R sin 4 5^{\circ} = \frac{10}{2} = 52 = 7.07 c m$ .

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Miscellaneous

⏱ 3mℹ️ Source: QB

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