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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

PhysicsMediuminteger

If a refracting surface of curvature 10 cm and refractive index 1.5. Find distance (in cm) of image formed from the surface of an object placed at 30 cm as shown.

Answer:

Solution:

Single refracting surface: $\frac{μ _{2}}{v} - \frac{μ _{1}}{u} = \frac{μ _{2} - μ _{1}}{R}$ .

$\frac{1.5}{v} - \frac{1}{- 30} = \frac{0.5}{10} \Rightarrow \frac{1.5}{v} = \frac{1}{60} \Rightarrow v = 90 cm$

Answer: 90

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

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