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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACMiscellaneousMedium3 minQB

PhysicsMediuminteger

A part of a complete circuit is shown in the figure. At some instant, the value of current I is 1 and it is decreasing at a rate of $1 0^{2} As^{- 1}$ . The value of the potential difference $V_{P} - V_{Q}$ , (in volts) at that instant, is :-

diagram

Answer:

Solution:

$L \frac{d i}{d t} = 5 V$ opposes the drop. Walking from P to Q:

$V_{P} - 5 - 30 + 2 \times 1 = V_{Q} \Rightarrow V_{P} - V_{Q} = 33 V$ .

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Miscellaneous

⏱ 3mℹ️ Source: QB

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