In the given figure the magnetic flux through the loop increases according to the relation $ϕ_{B} (t) = 10 t^{2} + 20 t$ , where $ϕ_{B}$ is in milliwebers and t is in seconds. The magnitude of current through $R = 2Ω$ resistor at $t = 5 s$ is $____$ mA.

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diagram

TestHub · Accepted Answer

∣ ε ∣ = d t d ϕ ​ = 20 t + 20 mV ; ∣ i ∣ = R ∣ ε ∣ ​ = 10 t + 10 m A . At t = 5 s: ∣ i ∣ = 60 m A .

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