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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsMedium3 minQB

PhysicsMediumsingle choice

A single wire $A CB$ passes through a smooth ring at $C$ which revolves at a constant speed in the horizontal circle of radius $r$ as shown in the fig. The speed of revolution is :-

diagram

Options:

Answer:

Solution:

$T cos 3 0^{\circ} + T cos 6 0^{\circ} = m g$ ; $T sin 6 0^{\circ} + T sin 3 0^{\circ} = \frac{m v ^{2}}{r}$ .

Dividing: $\frac{m v ^{2}}{r} = m g \Rightarrow v = r g$ - (A).

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 3mℹ️ Source: QB

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