Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICalculation of DSEasy2 minQB
ChemistryEasysingle choice
The entropy change accompanying the heating of one mole of neon gas (Cv,m = 3R/2, ideal) at constant pressure from 150 K to 1200 K is (R = 2 cal/K-mol, ln 2 = 0.7)
Options:
Answer:
A
Solution:
CP = 5R/2 = 5 cal/K-mol. Δ S = CPln(1200/150) = 5ln 8 = 5 × 3 × 0.7 = 10.5 cal/K. (Using CV gives the wrong value 6.3.) Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
⏱ 2mℹ️ Source: QB
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