Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IICarnot Cycle/Cyclic processMedium2 minQB
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Two moles of an ideal monoatomic gas undergo a cyclic process ABCA as shown in the figure. What is the ratio of temperature at B and A? (Axes drawn to equal scale.)

figure

Options:

Answer:
D
Solution:

A is (Vo, Po), C is (5Vo, Po), so AC = 4Vo. With B at height h: horizontal distance from A is h/tan 30° = h√(3) and from C is h/tan 60° = h/√(3). Sum: (4h)/(√(3)) = 4Vo, so h = √(3)Vo. Then VB = Vo + h√(3) = 4Vo, and PB = 4Po. TB/TA = (4Po × 4Vo)/(PoVo) = 16. Matches (d).

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
⏱ 2mℹ️ Source: QB

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