Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICarnot Cycle/Cyclic processMedium2 minQB
ChemistryMediumsingle choice
In which case will the efficiency of a Carnot cycle be higher: when the hot body temperature is increased by Δ T, or when the cold body temperature is decreased by the same magnitude?
Options:
Answer:
B
Solution:
η = 1 - Tc/Th. Case 1: η1 = 1 - Tc/(Th + Δ T). Case 2: η2 = 1 - (Tc - Δ T)/Th. Compare Tc/(Th+Δ T) with (Tc - Δ T)/Th: cross-multiplying, TcTh versus (Tc - Δ T)(Th + Δ T) = TcTh - Δ T(Th - Tc) - Δ T2 < TcTh since Th > Tc. So case 2 has the smaller ratio and the higher efficiency, whatever the initial temperatures. Matches (b).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
