Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IIFree Energy and EquilibriumMedium2 minQB
ChemistryMediumsingle choice
The vapour pressure of water is 0.04 atm at 27°C. The free energy change for the following process is
H₂O(g, 0.04 atm, 27°C) → H₂O(l, 0.04 atm, 27°C)
Options:
Answer:
A
Solution:
At 27°C the equilibrium vapour pressure of water is 0.04 atm, so vapour and liquid at 0.04 atm are in phase equilibrium; the chemical potentials are equal and ΔG = 0. Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Free Energy and Equilibrium
⏱ 2mℹ️ Source: QB
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