Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICalculation of DSMedium2 minQB
ChemistryMediumsingle choice
The change in entropy accompanying the heating of one mole of helium gas (Cv,m = 3R/2), assumed ideal, from a temperature of 250 K to a temperature of 1000 K at constant pressure. (ln 2 = 0.7)
Options:
Answer:
B
Solution:
CP = CV + R = 5R/2; with R = 2 cal/K-mol, CP = 5 cal/K-mol. Δ S = CPln(1000/250) = 5 ln 4 = 5 × 2 × 0.7 = 7.0 cal/K. Matches (b).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
⏱ 2mℹ️ Source: QB
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