Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICalculation of DSMedium2 minQB
ChemistryMediumsingle choice
Two blocks of copper metal are of same size (heat capacity = C) but at different temperatures T₁ and T₂. These blocks are brought together and allowed to attain thermal equilibrium. The entropy change of system is
Options:
Answer:
A
Solution:
Final temperature Tf = (T₁+T₂)/2. ΔS = C ln(Tf/T₁) + C ln(Tf/T₂) = C ln[(T₁+T₂)²/(4T₁T₂)]. Since (T₁+T₂)² = (T₂−T₁)² + 4T₁T₂, this equals C ln[(T₂−T₁)²/(4T₁T₂) + 1]. Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
