Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIGibb's Free EnergyMedium2 minQB

ChemistryMediummatching list

Match Column I (graph) with the physical quantity in Column II (area shown in the graph represents the magnitude of).

Answer:

Solution:

$dG = V \cdot dP - S \cdot dT$ $\Rightarrow (dG)_{T} = V \cdot dP and (dG)_{P} = - S \cdot Dt$

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy

⏱ 2mℹ️ Source: QB

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