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Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIGibb's Free EnergyMedium2 minQB
ChemistryMediumsingle choice

COLUMN-I COLUMN-II

(Sign of and respectively)(Nature of reaction)

(A) & (P) Spontaneous only at low temperature

(B) & (Q) Spontaneous only at high temperature

(C) & (R) Spontaneous at all temperatures

(D) & (S) Non-spontaneous at all temperatures

Options:

Answer:
A
Solution:

The spontaneity of a reaction is determined by the Gibbs Free Energy equation:

where a reaction is spontaneous if .

(A) (–), (–): is negative only when is small enough that . Matches (P) spontaneous at low temperatures.

 

(B) (–), (+): Both terms are negative, making always negative. Matches (R) spontaneous at all temperatures.

 

(C) (+), (+): becomes negative only when is large enough that . Matches (Q) spontaneous at high temperatures.

 

(D) (+), (–): Both terms are positive, so is always positive. Matches (S) non-spontaneous at all temperatures.

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy
2mℹ️ Source: QB

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