Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICarnot Cycle/Cyclic processEasy2 minQB
ChemistryEasysingle choice
A Carnot engine works between 727°C and 227°C. If it absorbs 150 cal of heat per cycle from the source, the heat rejected per cycle to the sink is
Options:
Answer:
D
Solution:
Th = 1000 K, Tc = 500 K. qc = qh × Tc/Th = 150 × 500/1000 = 75 cal. Matches (d).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
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