Δ H f o of X ( ℓ ) = − 240 kJ / mol Δ H f o of X ( g ) = − 236.8 kJ / mol Δ S Va p o of X ( ℓ ) = 40 J / mol At what temperature, equilibrium would be established between X(ℓ) and X(g) at 1 bar

Question

Δ H f o ​ of X ( ℓ ) = − 240 kJ / mol Δ H f o ​ of X ( g ) = − 236.8 kJ / mol Δ S Va p o ​ of X ( ℓ ) = 40 J / mol At what temperature, equilibrium would be established between X(ℓ) and X(g) at 1 bar pressure ? [Assume ΔH and ΔS to be independent of temperature change]

TestHub · Accepted Answer

X ( ℓ ) ⇌ X ( g ) , Δ vap ​ H = Δ f ​ H X ( g ) ​ − Δ f ​ H X ( l ) ​ = − 236.8 + 240 = 3.2 kJ / mol at equilibrium Δ vap ​ H = T Δ vap ​ S 3.2 × 1000 = T × 40 T = 80 K

Chemistry - Thermodynamics - II Question with Solution | TestHub

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