Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IIDS in chemical reactionHard2 minQB
ChemistryHardnumerical
Calculate Δ Suniv (in J/K) for the chemical reaction: C(graphite) + 2H2(g) → CH4(g); Δ H°300 = -75.0 kJ. The standard entropies of C (graphite), H2(g) and CH4(g) are 6.0, 130.6 and 186.2 J/K-mol, respectively.
Answer:
169.00
Solution:
Δ Ssys = 186.2 - (6.0 + 2×130.6) = -81.0 J/K. Δ Ssurr = -Δ H/T = 75000/300 = 250.0 J/K. Δ Suniv = 250.0 - 81.0 = 169 J/K. Ans = 0169.
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:DS in chemical reaction
⏱ 2mℹ️ Source: QB
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