Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICalculation of DSMedium2 minQB
ChemistryMediumsingle choice
A heat engine absorbs 50 kJ of heat from a source at 500 K, performs 15 kJ of work and rejects the remaining heat to a sink at 250 K. The entropy change of the universe per cycle is
Options:
Answer:
D
Solution:
Heat rejected = 50 - 15 = 35 kJ. Δ Ssource = -50000/500 = -100 J/K. Δ Ssink = +35000/250 = +140 J/K. The working substance returns to its initial state. Δ Suniverse = -100 + 140 = +40 J/K (positive, as expected for an irreversible engine: its efficiency 30% is below the Carnot limit of 50%). Matches (d).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
⏱ 2mℹ️ Source: QB
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