Chemistry - Thermodynamics - II Question with Solution | TestHub

Efficiency of cycle$=\frac{\text{Area of closed cycle}}{\text{Area of under the curve}}\times 100$

$=\frac{\frac{1}{2}\times (1500-1000)\times (250-150)}{\frac{1}{2}\times (1500-1000)\times (250-150)+(1500-1000)\times (150-0)}\times 100$

$=\frac{\frac{1}{2}\times 500\times 100}{\frac{1}{2}\times 500\times 100+500\times 150}$

$=\frac{500\times 50\times 100}{500\times 50+500\times 150}$

$=25$.