Chemistry - Thermodynamics - II Question with Solution | TestHub

At equilibrium $\Delta G=0$ $$\begin{array}{l}\text{ Hence, }\Delta G=\Delta H-T_e\Delta S=0\\ \therefore \Delta H=T_e\Delta S\text{ or }{T}_e=\frac{\Delta H}{\Delta S}\end{array}$$ For a spontaneous reaction $\Delta G$ must be negative which is possible only if $\Delta H-T\Delta S<0$ $\therefore \Delta H\frac{\Delta H}{\Delta S} ; T_{e}