The internal energy of a gas is given by U = 2.5 PV. It expands from 100 to 300 cm 3 against a constant pressure of 2.0×10 5 Pa. The heat absorbed (in J) by the gas in the process is

Δ U = 2.5PΔ V = 2.5×2.0×10 5 ×200×10 -6 = 100 J. w = PΔ V = 40 J. q = 100 + 40 = 140 J. Ans = 0140.

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The internal energy of a gas is given by U = 2.5 PV. It expands from 100 to 300 cm³ against a constant pressure of 2.0×10⁵ Pa. The heat absorbed (in J) by the gas in the process is

Answer:

140.00

Solution:

Δ U = 2.5PΔ V = 2.5×2.0×10⁵×200×10^-6 = 100 J. w = PΔ V = 40 J. q = 100 + 40 = 140 J. Ans = 0140.

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

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