Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IHeat & Heat CapacityMedium2 minQB
ChemistryMediumnumerical
Fifteen moles of a certain ideal gas at a temperature 400 K was cooled isochorically so that the gas pressure reduced 4.0 times. Then, as a result of the isobaric process, the gas expanded till its temperature got back to the initial value. The total amount of heat absorbed (in Kcal) by the gas in this process is
Answer:
9.00
Solution:
Isochoric: P quartered ⇒ T₂ = 400/4 = 100 K. Isobaric reheating to 400 K, ΔT = 300 K. Over the full process ΔU = 0, so net heat = net work = Wisobaric = nRΔT = 15 × 2 × 300 = 9000 cal = 9 kcal.
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Heat & Heat Capacity
⏱ 2mℹ️ Source: QB
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