Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minQB
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One mole of a real gas is taken from (3 bar, 20 L, 300 K) to (3 bar, 30 L, 450 K). The molar heat capacities of the gas at constant volume and constant pressure are 21 and 33 J/K-mol, respectively. What is the change in internal energy of the gas in this process?
Options:
Answer:
A
Solution:
Δ U = nCVΔ T = 1 × 21 × (450 - 300) = 3150 J. (Δ H = 33 × 150 = 4950 J is the enthalpy change, and PΔ V = 3 × 10 = 30 bar-L = 3000 J is the work magnitude.) Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
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