Chemistry - Thermodynamics - I Question with Solution | TestHub
An adiabatic cylinder fitted with an adiabatic piston at the right end is divided into two equal halves, with a diatomic gas on the left side and a monoatomic gas on the right side, using an impermeable movable adiabatic wall. Both gases are initially at the same pressure. If the piston is pushed slowly to compress the monoatomic gas to 2/3rd of its original volume, the ratio of the new volume of the diatomic gas to its initial volume would be
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Answer:
Solution:
Both gases change reversibly and adiabatically and stay at equal pressure. Monoatomic (γ = 5/3): P = P0(3/2)5/3. Diatomic (γ = 7/5): P = P0(V0/Vd)7/5. Equating: (V0/Vd)7/5 = (3/2)5/3, so Vd/V0 = (2/3)25/21. Matches (a). Trap: the exponent is the ratio of the gamma values, with 5/3 over 7/5 = 25/21, not its inverse.
