Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsHard2 minQB
ChemistryHardnumerical
A system undergoes a certain change in state by path I and the corresponding heat absorbed and work done are 10 kcal and 0 erg, respectively. For the same change in state by path II, the respective quantities are 11 kcal and 0.5 wmax, where wmax represents the work done if the changes were reversibly carried out. The magnitude of wmax in J, is (1 cal = 4.2 J)
Answer:
8400.00
Solution:
Path I: Δ U = q - w = 10 - 0 = 10 kcal (state function). Path II: 10 = 11 - 0.5 wmax, so 0.5 wmax = 1 kcal, wmax = 2 kcal = 2000×4.2 = 8400 J. Ans = 8400.
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: QB
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