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ChemistryThermodynamics - IAdiabatic Process/PolytropicMedium2 minQB
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An adiabatic cylinder fitted with an adiabatic piston at the right end of cylinder, is divided into two equal halves with a monoatomic gas on left side and diatomic gas on right side, using an impermeable movable adiabatic wall. If the piston is pushed slowly to compress the diatomic gas to 3/4th of its original volume. The ratio of new volume of monoatomic gas to its initial volume would be

Options:

Answer:
C
Solution:

Each gas is compressed reversibly and adiabatically, and the two pressures stay equal (movable wall). Initially both halves have the same pressure P0 and volume V0. Diatomic (γ = 7/5): P = P0(4/3)7/5. Monoatomic (γ = 5/3): P = P0(V0/Vm)5/3. Equating: (V0/Vm)5/3 = (4/3)7/5, so Vm/V0 = (3/4)21/25. Matches (c).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic
⏱ 2mℹ️ Source: QB

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