Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minQB
ChemistryMediumnumerical

The pressure over 500 ml of a liquid is gradually raised from 1 bar to 401 bar under adiabatic conditions. The final volume is 497 ml, with volume varying linearly with pressure. The value of Δ U is (Answer as 'abcd', where a = 1 if Δ U is +ve and a = 2 if Δ U is -ve, and 'bcd' is the magnitude of Δ U in J, nearest integer)

Answer:
1060.00
Solution:

Adiabatic: Δ U = -∫ P dV = Pavg|Δ V| = 201×3 = 603 bar ml = 60.3 J ≈ 60 J (+ve). Ans = 1060.

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: QB

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