The heat capacity of liquid water is 75.6 J/K-mol, while the enthalpy of fusion of ice is 6.0 kJ/mol. What is the smallest number of ice cubes at 0°C, each containing 18 g of water, needed to cool 360

Question

The heat capacity of liquid water is 75.6 J/K-mol, while the enthalpy of fusion of ice is 6.0 kJ/mol. What is the smallest number of ice cubes at 0°C, each containing 18 g of water, needed to cool 360 g of liquid water from 25°C to 0°C?

TestHub · Accepted Answer

Heat to remove: q = 360/18(75.6)(25) = 20 × 1890 = 3.78×10 4 J. Each cube is 1 mol and absorbs 6000 J on melting. 37800/6000 = 6.3, so 7 cubes are needed (6 would not reach 0°C). Matches (b).

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