Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IWorkMedium2 minQB
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Passage / Comprehension
An ideal gas (CP/Cv = γ) is expanded so that the amount of heat transferred to the gas is equal to the decrease in its internal energy.
What is the magnitude of work performed by one mole of the gas when its volume increases 8 times if the initial temperature of the gas is 300 K? Cv,m for the gas is 1.5R.
Options:
Answer:
A
Solution:
Cv,m = 1.5R gives γ = 5/3, so (γ-1)/2 = 1/3. T2 = T1 (V1/V2)1/3 = 300 × 8-1/3 = 150 K. Since q = -Δ U, w = q - Δ U = -2Δ U. Δ U = 1.5R(150-300) = -225R, so |w| = 450R = 450 × 2 = 900 cal (R = 2 cal/mol K). Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Work
⏱ 2mℹ️ Source: QB
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