A volume of 100 ml of a liquid contained in an isolated container at a pressure of 1 bar. The pressure is steeply increases to 100 bar by which the volume of liquid is decreased by 1 ml. The change in

Question

A volume of 100 ml of a liquid contained in an isolated container at a pressure of 1 bar. The pressure is steeply increases to 100 bar by which the volume of liquid is decreased by 1 ml. The change in enthalpy, Δ H, of the liquid is (Answer as 'abcd', where a = 1, if Δ H is +ve and a = 2, if Δ H is -ve, and 'bcd' is the magnitude of Δ H, in J)

TestHub · Accepted Answer

Isolated container: q = 0, w = 0, so Δ U = 0. Δ H = Δ U + Δ(PV) = P 2 V 2 - P 1 V 1 = 100×99 - 1×100 = 9800 bar ml = 9800×0.1 J = 980 J (positive). a = 1, bcd = 980. Ans = 1980.

Chemistry - Thermodynamics - I Question with Solution | TestHub

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