Three moles of an ideal gas (C P,m = 2.5R) and 2 moles of another ideal gas (C P,m = 3.5R) are taken in a vessel and compressed reversibly and adiabatically. In this process, the temperature of gaseou

Question

Three moles of an ideal gas (C P,m = 2.5R) and 2 moles of another ideal gas (C P,m = 3.5R) are taken in a vessel and compressed reversibly and adiabatically. In this process, the temperature of gaseous mixture increased from 300 K to 400 K. The increase in internal energy of gaseous mixture (in cal) is

TestHub · Accepted Answer

C V : gas 1 = 1.5R, gas 2 = 2.5R. C V,total = 3(1.5R) + 2(2.5R) = 9.5R. Δ U = 9.5R×100 = 950R = 950×2 cal = 1900 cal (R ≈ 2 cal/K-mol). Ans = 1900.

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