Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IAdiabatic Process/PolytropicMedium2 minQB
ChemistryMediummultiple choice

Two moles of an ideal gas (Cv,m = 1.5R) is subjected to the following changes in states:

A (500 K, 5 bar) →(Reversible Isothermal Expansion) B →(Isochoric Cooling) C (250 K, 1 bar) →(Single stage adiabatic compression) D (3 bar)

The correct statement(s) is/are

Options:(select one or more)

Answer:
A, B, C
Solution:

B to C is at constant V, so PB/TB = PC/TC gives PB = 1 × 500/250 = 2 bar: (a) true. For C to D, the single-stage compression is against Pext = 3 bar, q = 0: nCv(TD - 250) = -Pext(VD - VC). VC = 2R(250)/1 = 500R, VD = 2RTD/3. So 3R(TD - 250) = -2RTD + 1500R, 5TD = 2250, TD = 450 K: (b) true. Δ HCD = 2(2.5R)(200) = 1000R: (c) true. Δ UBC = 2(1.5R)(-250) = -750R, not 375R: (d) false. Ans: (a), (b), (c).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic
⏱ 2mℹ️ Source: QB

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