Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IHeat & Heat CapacityHard2 minQB
ChemistryHardsingle choice
One mole of an ideal gas undergoes a reversible process T = T0 + α V2, where T0 and α are constants. If its volume increases from V1 to V2, the amount of heat transferred to the gas is
Options:
Answer:
C
Solution:
Δ T = α(V22 - V12), so Δ U = (CP,m - R)α(V22 - V12). W = ∫ (RT)/VdV = ∫ ((RT0)/V + Rα V)dV = RT0ln(V2)/(V1) + (Rα)/2(V22 - V12). Q = Δ U + W = α(CP,m - R + R/2)(V22 - V12) + RT0ln(V2)/(V1), which is (c). Trap: using dV instead of d(V2) gives (d), and forgetting the work term from the α V2 part gives (b).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Heat & Heat Capacity
⏱ 2mℹ️ Source: QB
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