Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minQB
ChemistryEasysingle choice
An insulated container has two chambers separated by an insulating partition. Chamber 1 has volume 2 L and holds an ideal gas at 2 atm and 300 K. Chamber 2 has volume 3 L and holds the same gas at 1 atm and 400 K. If the partition is removed without doing any work on the gas, the final equilibrium temperature will be
Options:
Answer:
A
Solution:
Δ U = 0, so T = (T1T2(P1V1 + P2V2))/(P1V1T2 + P2V2T1). P1V1 = 4, P2V2 = 3 L-atm. T = (300 × 400 × 7)/(4(400) + 3(300)) = 840000/2500 = 336 K. Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: QB
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