Two moles of an ideal gas (C P,m = 2.5R) and 4 moles of another ideal gas (C P,m = 3.5R) are compressed reversibly and adiabatically in a vessel, raising the temperature of the mixture from 300 K to 3

Question

Two moles of an ideal gas (C P,m = 2.5R) and 4 moles of another ideal gas (C P,m = 3.5R) are compressed reversibly and adiabatically in a vessel, raising the temperature of the mixture from 300 K to 380 K. The increase in internal energy of the mixture (in cal) is (R = 2 cal/K-mol)

TestHub · Accepted Answer

C V = 1.5R and 2.5R. C V,total = 2(1.5R) + 4(2.5R) = 13R. Δ U = 13R×80 = 1040R = 2080 cal. Ans = 2080.

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