Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minQB
ChemistryEasysingle choice
Passage / Comprehension
An amount of 3 mole of nitrogen gas is taken in a rigid vessel at 27°C and 1 atm and the vessel is sealed. Now the gas is heated to 107°C. (Take R = 2 cal/mol K; treat N2 as an ideal diatomic gas.)
What is the change in internal energy of the gas?
Options:
Answer:
A
Solution:
Rigid vessel, so V is constant. Δ T = 380 - 300 = 80 K. Cv,m = 5/2R = 5 cal/mol K. Δ U = 3 × 5 × 80 = 1200 cal. Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
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