As 1 mole of liquid water is heated from 288 to 298 K, it expands slightly against the atmosphere. Given coefficient of cubic expansion of water is 0.0002/°C; density of water = 1.0 g cm⁻³ and externa

Question

As 1 mole of liquid water is heated from 288 to 298 K, it expands slightly against the atmosphere. Given coefficient of cubic expansion of water is 0.0002/°C; density of water = 1.0 g cm⁻³ and external pressure = 1 bar. If the magnitude of work for this process is X J, then the value of X/(6×10⁻⁴) is

TestHub · Accepted Answer

Volume of 1 mol water = 18 cm³ = 18×10⁻⁶ m³. ΔV = V·γ·ΔT = 18×10⁻⁶ × 2×10⁻⁴ × 10 = 3.6×10⁻⁸ m³. Expansion work against 1 bar: W = P e xt·ΔV = 10⁵ Pa × 3.6×10⁻⁸ m³ = 3.6×10⁻³ J = X. Then X/(6×10⁻⁴) = 3.6×10⁻³/(6×10⁻⁴) = 6.

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