Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IWorkHard2 minQB
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Passage / Comprehension
An amount of 3 mole of nitrogen gas is taken in a rigid vessel at 27°C and 1 atm and the vessel is sealed. Now the gas is heated to 107°C. (Take R = 2 cal/mol K; treat N2 as an ideal diatomic gas.)
The sealed vessel is replaced by a cylinder with a frictionless piston held at constant external pressure, and 3 mole of the same gas is heated through the same temperature rise (300 K to 380 K). What is the magnitude of work done by the gas in this case?
Options:
Answer:
C
Solution:
Now the pressure is constant, so the volume grows and w = PΔ V = nRΔ T = 3 × 2 × 80 = 480 cal. In the rigid vessel the work was zero; heat absorbed here is nCp,mΔ T = 1680 cal, of which 1200 cal raises U and 480 cal is work. Matches (c).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Work
⏱ 2mℹ️ Source: QB
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