Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IAdiabatic Process/PolytropicMedium2 minQB
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Passage / Comprehension
The adiabatic compression of a mixture of 2 volumes of Hydrogen and 1 volume of oxygen from 320 ml to 10 ml caused explosion. The initial pressure and temperature of the gaseous mixture were 1 atm and 27°C.
What is the magnitude of maximum work performed by the gaseous mixture before explosion?
Options:
Answer:
B
Solution:
Moles of mixture n = PV/RT = (1 atm × 0.320 L)/(0.0821 L-atm/K-mol × 300 K) ≈ 0.013 mol. In adiabatic compression q = 0, so |w| = |ΔU| = n·Cv·ΔT = 0.013 × (5/2 × 8.314) × (1200 − 300) ≈ 0.013 × 20.785 × 900 ≈ 243.1 J. (The gas itself does negative work during compression; the magnitude of the work exchanged is 243.12 J.) Matches (b).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic
⏱ 2mℹ️ Source: QB
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