500 J of energy is transferred as heat to 0.5 mol of Argon gas at 298 K and 1.00 atm. The final temperature and the change in internal energy respectively are: Given : R = 8.3 J K − 1 mol − 1

Question

TestHub · Accepted Answer

​ q p ​ = n × c p ​ × Δ T ⇒ 500 = 0.5 × 2 5 ​ × 8.3 ( T f ​ − 298 ) ⇒ T f ​ ≃ 346.2 K Δ U Δ H ​ = C v ​ C p ​ ​ = ( 3 5 ​ ) ⇒ Δ U = 5 3 ​ × 500 = 300 J ​

Chemistry - Thermodynamics - I Question with Solution | TestHub

Options:

Doubts & Discussion