For the following reaction at 300 K A 2 ( g ) + 3 B 2 ( g ) → 2 AB 3 ( g ) the enthalpy change is +15 kJ then the internal energy change is:NEET 2024 (Re-NEET)

Question

For the following reaction at 300 K A 2 ​ ( g ) + 3 B 2 ​ ( g ) → 2 AB 3 ​ ( g ) the enthalpy change is +15 kJ then the internal energy change is:NEET 2024 (Re-NEET)

TestHub · Accepted Answer

A 2 ​ ( g ) + 3 B 2 ​ ( g ) → 2 AB 3 ​ ( g ) Δ n ( g ) ​ = n ( P ) ​ − n ( R ) ​ = 2 − 3 − 1 = − 2 Δ H = Δ U + Δ n g ​ RT 15 × 1000 = Δ U − 2 × 8.314 × 300 Δ U = 15000 + 600 × 8.314 = 15000 + 6 × 831.4 = 15000 + 4988.4 Δ U = 19988.4 J

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