The work done during reversible isothermal expansion of one mole of hydrogen gas at 2 5 ∘ C from pressure of 20 atmosphere to 10 atmosphere is (Given R = 2.0 cal K − 1 mol − 1 )NEET 2024

W rev, iso = − 2.303 n RT lo g P f P i = − 2.303 × 1 × 2 × 298 × lo g 2 = − 2.303 × 1 × 2 × 298 × 0.3 = − 413.14 calories

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ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2024

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The work done during reversible isothermal expansion of one mole of hydrogen gas at $2 5^{\circ} C$ from pressure of 20 atmosphere to 10 atmosphere is (Given $R = 2.0 cal K^{- 1} mol^{- 1}$ )NEET 2024

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Solution:

$W_{rev, iso} = - 2.303 n RT lo g \frac{P _{i}}{P _{f}} = - 2.303 \times 1 \times 2 \times 298 \times lo g 2 = - 2.303 \times 1 \times 2 \times 298 \times 0.3 = - 413.14 calories$

Stream:NEETSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2024

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