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ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minPYQ_2021
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At 25°C,50 g of iron reacts with HCl to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is -_______ J.

(Round off to the Nearest Integer)

[Given : R=8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas]

[Atomic mass off Fe is 55.85 u]

Answer:
2218
Solution:

T=298 K, R=8.314 JmolK

Chemical reaction is  

Fe50g+2HClFeCl2P=1 bar+H2g

=5055.85 mol

Work done for 1 mol gas

=-Pext×ΔV

=ΔngRT

=-1×8.314×298 J

Work done for 5055.85 mol of gas

=-8.314×298×5055.85 J

=-2218.059 J

-2218 J

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
2mℹ️ Source: PYQ_2021

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