Chemistry - Thermodynamics - I Question with Solution | TestHub

Given number of moles =1
Initial temperature$={27}^{\text{o}}\text{C}=300\text{K}$
Work done by the system$=3\text{kJ}=3000\text{K}$
It will be$(-)$because work is done by the system.
Heat capacity at constant volume$\left(\text{Cv}\right)\text{=}\text{20}\text{J/k}$
We know that work done
$\mathrm{W}=-\mathrm{n}{\mathrm{C}}_{\mathrm{V}}\mathrm{}({\mathrm{T}}_2-{\mathrm{T}}_1)$;
$3000=-1\times 20\mathrm{}({\mathrm{T}}_2-300)$
$3000=-20{\mathrm{T}}_2+6000$
$20{\text{T}}_{\text{2}}=3000{\text{T}}_{\text{2}}=\frac{3000}{20}=150\text{K}$