Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2020

ChemistryEasysingle choice

In the cyclic process shown in P-V diagram, the magnitude of the work done is

Answer:

Solution:

Work done = Area bounded by the circle
$= π \frac{(P_{2} - P_{1})}{2} \frac{(V_{2} - V_{1})}{2}$
$= \frac{π}{4} (P_{2} - P_{1}) (V_{2} - V_{1})$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2020

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