Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2020

ChemistryEasysingle choice

The enthalpy changes for given reaction at 298 K is - x cal/mol. If the reaction occurs spontaneously at 298 K, the entropy change at that temperature

Options:

Answer:

Solution:

$Δ G = Δ H - T Δ S$

For a spontaneous process, $Δ H - T Δ S < 0$ .

So, $ΔS > \frac{ΔH}{T} = \frac{- \frac{x cal}{mol}}{298 K}$

Hence, $Δ S$ is numerically smaller than $\frac{x}{298} cal {mol}^{- 1} K^{- 1}$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2020

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