Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2020
ChemistryEasysingle choice

The standard enthalpy of neutralization of strong acid and strong base is-57.3kJ equiv −1 . If the enthalpy of neutralization of the first proton of aqueousH2Sis-33.7kJmol-1then the pK a 1 ofH2Sis

Options:

Answer:
A
Solution:

H2S⇌H++HS-
ΔHion=23.6kJ
∴ΔG°=23.6×103-TΔS°=-2.303RTlogKa1
∴PKa1=23.6×103-TΔS°2.303RT

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: PYQ_2020

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