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Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2019

ChemistryEasysingle choice

At $2 5^{\circ} C$ , when 1 mole of butane is heated, $CO_{2}$ and liquid $H_{2} O$ are formed, then the work done is

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Answer:

Solution:

$C_{4} H_{10 (g)} + \frac{13}{2} O_{2 (g)} ⟶ 4 CO_{2 (g)} + 5 H_{2} O_{(l)} Δ n_{g} = 4 - (1 + \frac{13}{2}) = - \frac{7}{2} w = - Δ n_{g} RT = - (- \frac{7}{2} \times 0.0821 \times 298) = 85.63 L atm$

Stream:AIIMSSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2019

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