Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minPYQ_2016

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If $100 mole$ of $H_{2} O_{2}$ decompose at $1 bar$ and $300 K$ , the work is done ( $kJ$ ) by one mole of $O_{2} (g)$ as it expands against $1 bar$ pressure is:

$2 H_{2} O_{2} (l) ⇌ 2 H_{2} O (l) + O_{2} (g)$

$(R = 8 .3 J K^{- 1} {mol}^{- 1})$

Options:

Answer:

Solution:

Irreversible process

$W = P ∆ V = nRT$

$\underset{}{\underset{100 mol}{2 H_{2} O_{2}}} (l) ⇌ \underset{}{2 \underset{}{H_{2} O} (l)} + \underset{\begin{array}{l} 50 mol \end{array}}{O_{2}} (g)$

$∴$ $100 mol H_{2} O_{2}$ on decomposition will give $50 mol O_{2}$

$= 50 \times 8.3 \times 300$

$= 124500 J$

$=124.50 kJ$

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2016

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